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伺服电机的型号怎么选择?

来源:http://www.jnmcd.com 发布时间:2019-02-04 浏览:
一、转速和编码器分辨率的确认。
1. Verification of speed and encoder resolution.
二、电机轴上负载力矩的折算和加减速力矩的计算。
2. Conversion of load moment on motor shaft and calculation of acceleration and deceleration moment.
三、计算负载惯量,惯量的匹配,安川伺服电机为例,部分产品惯量匹配可达50倍,但实际越小越好,这样对精度和响应速度好。
3. Calculate the load inertia, inertia matching. As an example, the inertia matching of some products can reach 50 times, but the smaller the actual, the better the accuracy and response speed.
四、再生电阻的计算和选择,对于伺服,一般2kw以上,要外配置。
Fourth, the calculation and selection of regenerative resistance, for servo, generally more than 2 kw, external configuration.
山东微型电机
五、电缆选择,编码器电缆双绞屏蔽的,对于安川伺服等日系产品绝对值编码器是6芯,增量式是4芯。
Fifth, cable selection, twisted-pair shielded encoder cable, for Japanese products such as Anchuan servo absolute encoder is 6 cores, incremental is 4 cores.
这里只考虑电机的动力问题,对于直线运动用速度v(t),加速度a(t)和所需外力F(t)表示,对于旋转运动用角速度 (t),角加速度 (t)和所需扭矩T(t)表示,它们均可以表示为时间的函数,与其他因素无关。很显然。电机的最大功率P电机,最大应大于工作负载所需的峰值功率P峰值,但仅仅如此是不够的,物理意义上的功率包含扭矩和速度两部分,但在实际的传动机构中它们是受限制的。用 峰值,T峰值表示最大值或者峰值。电机的最大速度决定了减速器减速比的上限,n上限= 峰值,最大/ 峰值,同样,电机的最大扭矩决定了减速比的下限,n下限=T峰值/T电机,最大,如果n下限大于n上限,选择的电机是不合适的。反之,则可以通过对每种电机的广泛类比来确定上下限之间可行的传动比范围。只用峰值功率作为选择电机的原则是不充分的,而且传动比的准确计算非常繁琐。
In this paper, only the dynamic problem of motor is considered. For linear motion, it is expressed by velocity v (t), acceleration a (t) and required external force F (t), and for rotary motion, it is expressed by angular velocity (t), angular acceleration (t) and required torque T (t), which can be expressed as functions of time, independent of other factors. Obviously. The maximum power P motor of the motor should be greater than the peak power P required by the workload, but that is not enough. The power in physical sense includes two parts: torque and speed, but they are limited in the actual transmission mechanism. The peak value, T peak, represents the maximum value or peak value. The maximum speed of the motor determines the upper limit of the deceleration ratio of the reducer. The upper limit of n is equal to the peak value and the maximum/peak value. Similarly, the maximum torque of the motor determines the lower limit of the deceleration ratio. The lower limit of n is equal to the peak value of T/T motor. The maximum limit of n is greater than the upper limit of n, so the motor chosen is inappropriate. Conversely, a wide analogy of each motor can be used to determine the feasible range of transmission ratios between the upper and lower limits. The principle of selecting motor only by peak power is not sufficient, and the accurate calculation of transmission ratio is very complicated.
上述选型计算比较麻烦,有时也需要,还可以选择的方法是:
The above selection calculation is troublesome and sometimes necessary. The alternative method is:
一种新的选择原则是将电机特性与负载特性分离开,并用图解的形式表示,这种表示方法使得驱动装置的可行性检查和不同系统间的比较更方便,另外,还提供了传动比的一个可能范围。这种方法的优点:适用于各种负载情况;将负载和电机的特性分离开;有关动力的各个参数均可用图解的形式表示并且适用于各种电机。因此,不再需要用大量的类比来检查电机是否能够驱动某个特定的负载。
A new selection principle is to separate the motor characteristics from the load characteristics and to express them graphically. This representation method makes it easier to check the feasibility of the driving device and compare different systems. In addition, it also provides a possible range of the transmission ratio. The advantages of this method are: it is suitable for all kinds of loads; it separates the characteristics of loads and motors; the parameters of power can be expressed graphically and applied to all kinds of motors. Therefore, it is no longer necessary to use a large number of analogies to check whether the motor can drive a specific load.
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